Swift Collections - Set

SwiftCollectionsSet.swift

//SETS

//CREATE

//immutable - using array literal
let mazdas: Set = ["2", "3", "3", "6", "CX-3", "CX-5", "CX-9", "MX-5", "CX-30"]

let oldMazdas: Set<String>
oldMazdas = ["323", "626"]

//mutable - using initialiser syntax
var europeanMazdas = Set<String>(["2", "3", "3", "6", "CX-3", "CX-5", "CX-30"])
var americanMazdas: Set = ["2", "3", "3", "6", "CX-3", "CX-5", "CX-9", "MX-5", "MX-5"]

//check if set is empty
mazdas.isEmpty

//check amount of elements in set
mazdas.count

//ADD DATA
europeanMazdas.insert("MX-5")

//check if element already exists in set
europeanMazdas.contains("MX-5")

//ITERATE
//for model in mazdas {
//    print(model.uppercased())
//}

//REMOVE DATA
//europeanMazdas.remove("MX-5")

//remove all elements at once
//europeanMazdas.removeAll()


//SET ALGEBRA https://en.wikipedia.org/wiki/Algebra_of_sets

//SUBTRACT (remove elements of one set, from another one)
let mazdasUnavailableInEurope = mazdas.subtracting(europeanMazdas)
//print(mazdasUnavailableInEurope)

//INTERSECT (returns common objects, which are in both sets)
let globalMazdaModels = europeanMazdas.intersection(americanMazdas)
//print(globalMazdaModels)

//UNION (returns all objects from both sets, without duplicates)
let allMazdas = americanMazdas.union(europeanMazdas)
print(allMazdas)

//SUBSET (checks if all elements of one set are also in another)
europeanMazdas.isSubset(of: mazdas)
europeanMazdas.isSubset(of: americanMazdas)
mazdas.isSubset(of: mazdas) //returns true if both sets contain exactly same elements
mazdas.isStrictSubset(of: mazdas) //returns false if both sets contain exactly same elements

//SUPERSET (checks if one set contains all elements of another)
mazdas.isSuperset(of: europeanMazdas) //returns true if both sets contain exactly same elements
mazdas.isStrictSuperset(of: europeanMazdas) //returns false if both sets contain exactly same elements

//DISJOINT (checks if there is no overlap between sets)
let tesla: Set = ["S", "X", "Y"]
tesla.isDisjoint(with: mazdas)