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tomhartley/gist:90f7361cd0995a39bc7f

Created March 23, 2015 19:59
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OK, datasheet says:
2.35V at 34 mA for the heater
So assuming you want to power it off 5V, you want the voltage drop across the resistor to be 2.65V (5-2.35). The current through the resistor will be the same as through the heater since they're in series so:
V=IR
2.65=0.034*R
R = 2.65/0.034 = 78 Ohms
The resistor for sensing can be anything above 1k, I reccomend starting with about 10K.
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