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Brute-force python code to check isomorphism between graphs
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import itertools | |
import numpy as np | |
def get_graph_order(adj_matrix): | |
if len(adj_matrix) != len(adj_matrix[0]): | |
return -1 | |
else: | |
return len(adj_matrix) | |
def get_degree_sequence(adj_matrix): | |
degree_sequence = [] | |
for vertex in range(len(adj_matrix)): | |
degree_sequence.append(sum(adj_matrix[vertex])) | |
degree_sequence.sort(reverse=True) | |
return degree_sequence | |
def get_all_vertex_permutations(adj_matrix): | |
if get_graph_order(adj_matrix) > 8: | |
print("This function is too inefficient for graph order > 8") | |
return -1 | |
all_adj_matrix = [] | |
idx = list(range(len(adj_matrix))) | |
possible_idx_combinations = [ | |
list(i) for i in itertools.permutations(idx, len(idx)) | |
] | |
for idx_comb in possible_idx_combinations: | |
a = adj_matrix | |
a = a[idx_comb] | |
a = np.transpose(np.transpose(a)[idx_comb]) | |
all_adj_matrix.append({ | |
"perm_vertex": | |
idx_comb, | |
"adj_matrix": | |
a | |
}) | |
return all_adj_matrix | |
def brute_force_test_graph_isomporphism(adj_1, adj_2): | |
degree_sequence_1 = get_degree_sequence(adj_1) | |
degree_sequence_2 = get_degree_sequence(adj_2) | |
if get_graph_order(adj_1) != get_graph_order(adj_1): | |
return False | |
elif np.array_equal(degree_sequence_1, degree_sequence_2) == False: | |
return False | |
else: | |
for adj_matrix in list( | |
map(lambda matrix: matrix["adj_matrix"], | |
get_all_vertex_permutations(adj_2))): | |
if np.array_equal(adj_1, adj_matrix) == True: | |
return True | |
return False |
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