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Created December 20, 2013 04:32
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\documentclass[12pt]{article}
\usepackage{amsmath} % flere matematikkommandoer
\usepackage[utf8]{inputenc} % æøå
\usepackage[T1]{fontenc} % mere æøå
\usepackage[danish]{babel} % orddeling
\usepackage{verbatim} % så man kan skrive ren tekst
\usepackage[all]{xy} % den sidste (avancerede) formel i dokumentet
\usepackage{listings}
\lstset{
numbers=left
}
% http://anthony.liekens.net/index.php/LaTeX/VectorNormNotation
\newcommand{\vectornorm}[1]{\left\|#1\right\|}
\title{Projekt B}
\begin{document}
\maketitle
\pagebreak
\section*{Opgave 2}
I opgaven er nedenstående givet
$$
V_1 =
\begin{pmatrix}
1\\
2\\
4\\
2
\end{pmatrix}
$$
Og
$$
V_2 =
\begin{pmatrix}
-3\\
4\\
3\\
4
\end{pmatrix}
$$
\subsection*{(a)}
Ved at benytte Gram–Schmidt proceduren søges en ortonormal basis ${q_1, q_2}$ for $V$.
$$
q_1 = \frac{1}{\vectornorm{v_1}}v_1 = \frac{1}{5} \begin{pmatrix}1\\ 2\\ 4\\ 2\\\end{pmatrix} = \begin{pmatrix}\frac{1}{5}\\ \frac{2}{5}\\ \frac{4}{5}\\ \frac{2}{5}\\\end{pmatrix}
$$
$$
q_2 = v_2 - Proj_{v_1} v_2 = v_2 - \left(v_2\cdot q_1\right) q_1
$$
$$
= \begin{pmatrix}-3\\ 4\\ 3\\ 4\end{pmatrix} - \left(\begin{pmatrix}-3\\ 4\\ 3\\ 4\end{pmatrix}\cdot \begin{pmatrix}\frac{1}{5}\\ \frac{2}{5}\\ \frac{4}{5}\\ \frac{2}{5}\\\end{pmatrix}\right) \begin{pmatrix}\frac{1}{5}\\ \frac{2}{5}\\ \frac{4}{5}\\ \frac{2}{5}\\\end{pmatrix}
$$
$$
= \begin{pmatrix}-3\\ 4\\ 3\\ 4\end{pmatrix} - 5\begin{pmatrix}\frac{1}{5}\\ \frac{2}{5}\\ \frac{4}{5}\\ \frac{2}{5}\\\end{pmatrix}
= \begin{pmatrix}-3\\ 4\\ 3\\ 4\end{pmatrix} - \begin{pmatrix}1\\ 2\\ 4\\ 2\end{pmatrix}
= \begin{pmatrix}-4\\ 2\\ -1\\ 2\end{pmatrix}
$$
$q_2$ skal dog lige normaliseres før denne, sammen med $q_1$, udgør ortonormal basis for $v$.
$$
q_2 = \frac{q_2}{\vectornorm{q_2}} = \frac{q_2}{5} = \begin{pmatrix}-4/5\\ 2/5\\ -1/5\\ 2/5\end{pmatrix}
$$
\subsection*{(b)}
\subsection*{(c)}
\end{document}
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