Created
October 8, 2016 11:11
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This C program has an array already saved in the source and it displays it; then requests a number from user, if the input number matches with any one in that array, it returns the position of that number in the array; otherwise, says that it is not in the array;
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#include <stdio.h> | |
int main() { | |
int data[11] = {10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60}; | |
int entry, i, position=1; | |
printf("Here is the array:\n"); | |
for (i=0; i<11; i++){ | |
printf("%d\t", data[i]); | |
} | |
printf("\n"); | |
printf("Enter your number which you want to know about:\n"); | |
scanf("%d", &entry); | |
for (i=0; i<11; i++){ | |
if (entry == data[i]){ | |
printf("The position of your number in that array is: %d\n", position); | |
break; | |
} else { | |
position++; | |
if (position > 11) { | |
printf("Seems like the number you entered is not in the array\n"); | |
break; | |
} | |
} | |
} | |
} |
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