Script to check computer's architecture

arch.cmd

echo Starting #%0 & @ECHO OFF & GOTO :windows

#### BASH SCRIPT STARTS HERE ####

# Check for OS name, but can't trust uname -a for arch
OS=`uname`

# Detect architecture by abusing an integer overflow
if ((1<<32)); then
    ARCH=64 # 64-bit architecture
else
    ARCH=32 # 32-bit architecture
fi

# $OS contains OS name, and $ARCH contains the architecture
clear
echo "Hello $OS $ARCH-bit user!"

# Exit before we run into the Windows code
read -n1 -r -p "Press any key to continue..." key
exit

:windows
::#### WINDOWS SCRIPT STARTS HERE ####

:: Determine the architecture by checking Windows' env vars.
IF %PROCESSOR_ARCHITECTURE% == x86 (
    SET ARCH=32
) ELSE (
    SET ARCH=64
)

:: %ARCH% contains the architecture of the OS
CLS
ECHO Hello Windows %ARCH%-bit user!

:: Exit so the script will not continue into the Linux code
PAUSE
EXIT

Instructions

Windows

• Double click 'arch.cmd'

Other Operating Systems (in a terminal)

• Make the script executable >_ chmod 777 arch.cmd
• Run the script >_ ./arch.cmd