A simple Python HTTP server that supports a GET that echoes some request data and a POST that reads a request body, parses it as JSON and responds with part of the data

simple_server.py

from BaseHTTPServer import BaseHTTPRequestHandler
import urlparse, json

class GetHandler(BaseHTTPRequestHandler):

    def do_GET(self):
        parsed_path = urlparse.urlparse(self.path)
        message = '\n'.join([
            'CLIENT VALUES:',
            'client_address=%s (%s)' % (self.client_address,
                self.address_string()),
            'command=%s' % self.command,
            'path=%s' % self.path,
            'real path=%s' % parsed_path.path,
            'query=%s' % parsed_path.query,
            'request_version=%s' % self.request_version,
            '',
            'SERVER VALUES:',
            'server_version=%s' % self.server_version,
            'sys_version=%s' % self.sys_version,
            'protocol_version=%s' % self.protocol_version,
            '',
            ])
        self.send_response(200)
        self.end_headers()
        self.wfile.write(message)
        return

    def do_POST(self):
        content_len = int(self.headers.getheader('content-length'))
        post_body = self.rfile.read(content_len)
        self.send_response(200)
        self.end_headers()

        data = json.loads(post_body)

        self.wfile.write(data['foo'])
        return

if __name__ == '__main__':
    from BaseHTTPServer import HTTPServer
    server = HTTPServer(('localhost', 8080), GetHandler)
    print 'Starting server at http://localhost:8080'
    server.serve_forever()

based on http://doughellmann.com/2007/12/pymotw-basehttpserver.html

To test the POST with curl:
curl -d '{"foo":1}' localhost:8080

Hi, I followed your tutorial, thanks.
But it can't handle special characters well...
I tried:

parsed_path = urlparse.urlparse(self.path)
query = parsed_path.query

But later, I fixed to:

parsed_path = urllib.parse.urlsplit(self.path)
query = urllib.parse.parse_qs(parsed_path.query)

And now it won't break. :)

Hello @trungly,

i found your code and tested it with Python 3.10. Due to the changes in python in between i had to fix some imports, etc.
This is the result:

from http.server import HTTPServer, BaseHTTPRequestHandler
from urllib.parse import urlparse
import json

class GetHandler(BaseHTTPRequestHandler):

    def do_GET(self):
        parsed_path = urlparse(self.path)
        message = '\n'.join([
            'CLIENT VALUES:',
            'client_address=%s (%s)' % (self.client_address,
                self.address_string()),
            'command=%s' % self.command,
            'path=%s' % self.path,
            'real path=%s' % parsed_path.path,
            'query=%s' % parsed_path.query,
            'request_version=%s' % self.request_version,
            '',
            'SERVER VALUES:',
            'server_version=%s' % self.server_version,
            'sys_version=%s' % self.sys_version,
            'protocol_version=%s' % self.protocol_version,
            '',
            ])
        self.send_response(200)
        self.end_headers()
        self.wfile.write(message.encode('utf-8'))
        return

    def do_POST(self):
        content_len = int(self.headers.getheader('content-length'))
        post_body = self.rfile.read(content_len)
        self.send_response(200)
        self.end_headers()

        data = json.loads(post_body)

        self.wfile.write(data['foo'])
        return

if __name__ == '__main__':
    server = HTTPServer(('localhost', 8080), GetHandler)
    print('Starting server at http://localhost:8080')
    server.serve_forever()

I now tried to curl this with http://localhost:8085/Hallo.txt?Arg1=4&arg4=3 . But the code does not get the second argument called arg4 here. Does anyone know why?

try this: curl http://localhost:8080/"Hallo.txt?Arg1=4&arg4=3"

try this: curl http://localhost:8080/"Hallo.txt?Arg1=4&arg4=3"

Thank you very much. To bad from my side. It helped a lot.