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June 16, 2019 06:16
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Typescript making undefined properties optional
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/** | |
* Get the keys of the properties to which U can be assigned. | |
*/ | |
type AssignableKeys<T, U> = { | |
[K in keyof T]: U extends T[K] ? K : never | |
}[keyof T]; | |
/** | |
* Get the interface containing only properties to which undefined can be assigned. | |
*/ | |
type UndefinableProperties<T> = { | |
[K in AssignableKeys<T, undefined>]: T[K] | |
} | |
/** | |
* Get all of the keys except those to which U can be assigned. | |
*/ | |
type IncompatibleKeys<T, U> = { | |
[K in keyof T]: U extends T[K] ? never : K | |
}[keyof T]; | |
/** | |
* Get the interface containing no properties to which undefined can be assigned. | |
*/ | |
type OmitUndefinableProperties<T> = { | |
[K in IncompatibleKeys<T, undefined>]: T[K] | |
} | |
/** | |
* Get the interface where all properties are optional. | |
*/ | |
type Optional<T> = {[K in keyof T]?: T[K]}; | |
/** | |
* Get the interface where properties that can be assigned undefined are | |
* also optional. | |
*/ | |
type UndefinedOptional<T> = OmitUndefinableProperties<T> & Optional<UndefinableProperties<T>>; |
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