Created
April 28, 2021 11:11
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//Given an array of non-negative integers nums, you are initially positioned at | |
//the first index of the array. | |
// | |
// Each element in the array represents your maximum jump length at that positio | |
//n. | |
// | |
// Determine if you are able to reach the last index. | |
// | |
// | |
// Example 1: | |
// | |
// | |
//Input: nums = [2,3,1,1,4] | |
//Output: true | |
//Explanation: Jump 1 step from index 0 to 1, then 3 steps to the last index. | |
// | |
// | |
// Example 2: | |
// | |
// | |
//Input: nums = [3,2,1,0,4] | |
//Output: false | |
//Explanation: You will always arrive at index 3 no matter what. Its maximum jum | |
//p length is 0, which makes it impossible to reach the last index. | |
// | |
// | |
// | |
// Constraints: | |
// | |
// | |
// 1 <= nums.length <= 3 * 104 | |
// 0 <= nums[i] <= 105 | |
// | |
// Related Topics 贪心算法 数组 | |
// 👍 1169 👎 0 | |
//leetcode submit region begin(Prohibit modification and deletion) | |
/** | |
* @param {number[]} nums | |
* @return {boolean} | |
*/ | |
var canJump = function (nums) { | |
let stack = [0]; | |
const visited = new Array(nums.length).fill(false); | |
while (stack.length) { | |
const index = stack.pop(); | |
if (visited[index]) { | |
continue; | |
} | |
visited[index] = true; | |
if (index == nums.length - 1) return true; | |
for (let i = 1; i <= nums[index]; i++) { | |
if (index + i < nums.length) { | |
stack.push(index + i); | |
} | |
} | |
} | |
return false; | |
}; | |
//leetcode submit region end(Prohibit modification and deletion) | |
const r = canJump([2, 3, 1, 1, 4]) | |
console.log(`r: ` + JSON.stringify(r, null, 4) + '\n') |
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