output a field within a JLayout

<?php echo $displayData->dpfields; ?>

<?php
foreach ($displayData->dpfields as $field) { $this->item->dpfields; if ($field->id == 1) { echo $field->value; }}
?>

The reason I choose id == 1 is because that is the field in the array that I wanted to display at that point.  If you wish to find out which number in the array to find your fields you can use 

echo "<pre>" . print_r($this->item->dpfields, true) . "</pre>";

////

<?php echo $displayData->jcfields; ?>

<?php
foreach ($displayData->jcfields as $field) { $this->item->jcfields; if ($field->id == 1) { echo $field->value; }}
?>

The reason I choose id == 1 is because that is the field in the array that I wanted to display at that point.  If you wish to find out which number in the array to find your fields you can use 

echo "<pre>" . print_r($this->item->jcfields, true) . "</pre>";