count_order_n3.py

def count_order_n3(n):
    results = []
    for a in range(1, n+1):
        for b in range(1, n+1):
            for c in range(1, n+1):
                d = a + b - c
                if a ** 3 + b ** 3 == c ** 3 + d ** 3:
                    results.append((a, b, c, d))
    return results