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A simple function to find the merge point of two Linked Lists in O(n) time and O(1) space
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| /*Make an interating pointer that goes forward every time till the end, and then jumps to the beginning of the opposite list, and so on. Create two of these, pointing to two heads. Advance each of the pointers by 1 every time, until they meet.*/ | |
| int FindMergeNode(Node *headA, Node *headB) | |
| { | |
| Node *p1 = headA; | |
| Node *p2 = headB; | |
| while(p1 != p2){ | |
| p1 = p1->next; | |
| p2 = p2->next; | |
| if(p1 == NULL) | |
| p1 = headB; | |
| if(p2 == NULL) | |
| p2 = headA; | |
| } | |
| return p1->data; | |
| } |
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Comparing the node addresses instead of the node data covers the case of Linked Lists having non unique elements.