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How to run scripts outside django
# coding: utf-8
import os
import django
os.environ.setdefault("DJANGO_SETTINGS_MODULE", "project.settings")
django.setup()
# write your code here
@ysharoiko
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ysharoiko commented Nov 17, 2017

In this case block in
if name == "main":
print 'LOOK'

will not work. Is it correct? or is there a way to use it?

@ysharoiko
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ysharoiko commented Nov 17, 2017

I was running
python ./manage.py shell < myscrip.py

If i run it just like
python myscrip.py

It gives me error
import(name)
ImportError: No module named project.settings

My script:

#!/home/django/Env/holter_dev/bin/python2

coding: utf-8

import os
import django

os.environ.setdefault("DJANGO_SETTINGS_MODULE", "project.settings")
django.setup()

if name == "main":
print 'LOOK'#!/home/django/Env/project/bin/python2

coding: utf-8

import os
import django

os.environ.setdefault("DJANGO_SETTINGS_MODULE", "project.settings")
django.setup()

if name == "main":
print 'LOOK'

@ysharoiko
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ysharoiko commented Nov 17, 2017

This code helped me to run script with main block

import os, sys

proj_path = "/path/to/my/project/"

This is so Django knows where to find stuff.

os.environ.setdefault("DJANGO_SETTINGS_MODULE", "myproject.settings")
sys.path.append(proj_path)

This is so my local_settings.py gets loaded.

os.chdir(proj_path)

This is so models get loaded.

from django.core.wsgi import get_wsgi_application
application = get_wsgi_application()

@nurettin
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nurettin commented Jan 2, 2020

at the root of your project create scripts/yourscript.py so that you have manage.py and scripts directoroy as siblings.
export DJANGO_SETTINGS_MODULE=your.settings
run ./manage.py runscript yourscript
this will load django environment and run your script within that.
you may consider putting the command in a Makefile to make it easier to manage for others.

Edit: Note that you need a run() function inside your script
Edit2:

as @geekyarthurs mentioned the above requires the RunScript extension https://django-extensions.readthedocs.io/en/latest/runscript.html

The way which I've found since then which doesn't require an extension is to create a script under:

<django project>/<a django app>/management/commands/yourcommand.py

make a class derived from BaseCommand and implement def handle(self, *args, **options):

@geekyarthurs
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geekyarthurs commented Nov 14, 2020

For anyone who's trying to use the above mentioned @nurettin you need to install django-extensions.

Further info : https://django-extensions.readthedocs.io/

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