URI 1118 python

uri.py

def get_input():
    inp = float(input())
    if inp > 10 or inp < 0:
        print("nota invalida")
        return get_input()
    else:
        return inp

def calculate():
    a = get_input()
    b = get_input()
    return (a + b)/2

def redo():
    X = float(input())
    print("novo calculo (1-sim 2-nao)")
    if X < 1 or X > 2:
        print("novo calculo (1-sim 2-nao)")
        redo()
    elif int(X) == 2:
        return False
    elif int(X) == 1:
        return True

while True:
    print("media = " + str(calculate()))
    x = redo()
    if not x:
        break

my code faced with run time error? can you please explain why it's happen my code is given below :
n = 0
c= 0
while 1:
x = float(input())
if(x >= 0 and x<=10.0):
n += 1
c += x
if n == 2:
print("media = %.2f"%(c/2))
n = 0
c = 0
temp = int(input("novo calculo (1-sim 2-nao)"))
if temp == 2:
break
elif temp == 1:
continue
else:
temp = int(input("novo calculo (1-sim 2-nao)"))

else:
    print("nota invalida")

my code faced with run time error? can you please explain why it's happen my code is given below :
n = 0
c= 0
while 1:
x = float(input())
if(x >= 0 and x<=10.0):
n += 1
c += x
if n == 2:
print("media = %.2f"%(c/2))
n = 0
c = 0
temp = int(input("novo calculo (1-sim 2-nao)"))
if temp == 2:
break
elif temp == 1:
continue
else:
temp = int(input("novo calculo (1-sim 2-nao)"))

else:
    print("nota invalida")

Your indentation is broke. Can you please fix it so that I can read it properly? Also, be more elaborate. What are you trying to achieve? And what sort of error you're getting?