Created
April 11, 2021 04:23
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def abbreviation(a: str, b: str) -> str: | |
dfs = [(len(a) - 1, len(b) - 1)] | |
dp = set() | |
while len(dfs) > 0: | |
pa, pb = dfs.pop() | |
if (pa, pb) in dp: | |
# (pa, pb) has already tested false | |
continue | |
dp.add((pa, pb)) | |
if pb < 0: | |
if pa < 0 or a[:pa+1].islower(): | |
# e.g. a[:pa+1] is either of the form | |
# "" or "xyz" | |
return "YES" | |
else: | |
# e.g. a[:pa+1] is of form "xYz" | |
continue | |
if pa < 0: | |
# a is empty while b has some characters | |
continue | |
if a[pa].isupper(): | |
if a[pa] == b[pb]: | |
# e.g. a[pa] == 'F' and b[pb] = 'F' | |
dfs.append((pa-1, pb-1)) | |
else: | |
# e.g. a[pa] == 'F' and b[pb] = 'G' | |
continue | |
else: | |
if a[pa].upper() == b[pb]: | |
# e.g. a[pa] == 'f' and b[pb] = 'F' | |
dfs.extend([(pa-1, pb-1), (pa-1, pb)]) | |
else: | |
# e.g. a[pa] == 'f' and b[pb] = 'G' | |
dfs.append((pa-1, pb)) | |
return "NO" |
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