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Find x^y mod p
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| // Find x^y mod p | |
| // Right-to-left method | |
| let modPow = (x, y, p) => { | |
| let res = 1; | |
| x %= p; | |
| while(y>0) { | |
| if (y%2 == 1) res = res*x % p | |
| y = Math.floor(y/2) | |
| x = x*x % p | |
| } | |
| return res; | |
| } | |
| console.log(modPow(50, 100, 13)) // 3 |
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