erase5.cpp

#include <bits/stdc++.h>
using namespace std;
int main()
{
	int N;
	vector <int> A;
	for(int i=1; i<=10; i++){
		cin>>N;
		A.push_back(N);
	}
	/*First 5 elements means L=0 and R=4*/
	A.erase(A.begin()+0,A.begin()+4+1);
	//^--Our formula  ^-L         ^-R
	for(int i=0; i<A.size(); i++)cout<<A[i]<<endl;
	return 0;	
}