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Generate unique XPATH for BeautifulSoup element
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#!/usr/bin/python | |
# -*- coding: utf-8 -*- | |
def xpath_soup(element): | |
# type: (typing.Union[bs4.element.Tag, bs4.element.NavigableString]) -> str | |
""" | |
Generate xpath from BeautifulSoup4 element. | |
:param element: BeautifulSoup4 element. | |
:type element: bs4.element.Tag or bs4.element.NavigableString | |
:return: xpath as string | |
:rtype: str | |
Usage | |
----- | |
>>> import bs4 | |
>>> html = ( | |
... '<html><head><title>title</title></head>' | |
... '<body><p>p <i>1</i></p><p>p <i>2</i></p></body></html>' | |
... ) | |
>>> soup = bs4.BeautifulSoup(html, 'html.parser') | |
>>> xpath_soup(soup.html.body.p.i) | |
'/html/body/p[1]/i' | |
>>> import bs4 | |
>>> xml = '<doc><elm/><elm/></doc>' | |
>>> soup = bs4.BeautifulSoup(xml, 'lxml-xml') | |
>>> xpath_soup(soup.doc.elm.next_sibling) | |
'/doc/elm[2]' | |
""" | |
components = [] | |
child = element if element.name else element.parent | |
for parent in child.parents: # type: bs4.element.Tag | |
siblings = parent.find_all(child.name, recursive=False) | |
components.append( | |
child.name if 1 == len(siblings) else '%s[%d]' % ( | |
child.name, | |
next(i for i, s in enumerate(siblings, 1) if s is child) | |
) | |
) | |
child = parent | |
components.reverse() | |
return '/%s' % '/'.join(components) | |
if __name__ == '__main__': | |
import doctest | |
doctest.testmod(verbose=True) |
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