Comp. Arch. hw.4Write a full program that add two 8 byte numbers and store result in 8 byte reserved memory location, called R.

bwdaddbuff.s

//
//  bwdaddbuff.s
//  bwdaddbuff
//
//  Created by Mahmut Bulut on 10/11/13.
//  Copyright (c) 2013 Mahmut Bulut. All rights reserved.
//

#.intel_syntax

    .data                       # .data segment
# Exemplary extra data set

# N1: .quad 0x11, 0x48, 0x23, 0x12, 0x71, 0x10, 0x47, 0x08

# N2: .quad 0x22, 0x43, 0x86, 0x92, 0x03, 0x05, 0x30, 0x82

N1: .byte 0x01, 0x02, 0x03, 0x04, 0x05, 0x06, 0x07, 0x08

N2: .byte 0x40, 0x40, 0x40, 0x40, 0x40, 0x40, 0x40, 0x40

# Addition of N1 and N2 results in ABCDEFGH

R: .fill 8, 1, 0x00             # Zero fill

    .text                       # .text segment
.globl _main
_main:
    pushl   %ebp                # push the stack base pointer reg to stack itself
    movl    %esp, %ebp          # move top stack pointer to base stack pointer to make it fillable
    subl    $24, %esp           # system call function stack resize

    movw $2, %cx                # count register fill
    iter:                       # iteration declaration
        movl    N1, %eax        # target data move
        movl    N2, %ebx        # addition data move
        addl    %ebx, %eax      # add
        movl    %eax, R         # copy to result
        movl    $R, (%esp)      # Result to stack pointer for usage puts
        cmpw    $1, %cx         # just for tests nothing so much
        je next4
    next4:
        movl    (N1)+4, %eax    # next 4 bytes
        movl    (N2)+4, %ebx
        addl    %ebx, %eax
        movl    %eax, (R)+4     # fill next 4 bytes
        movl    $R, (%esp)
    loop iter                   # loop is just for example it is not needed

    call    _puts               # print the stack segment pushed in with _puts

    xorl    %eax, %eax          # clear eax

    leave
    ret
    .subsections_via_symbols