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August 11, 2019 23:09
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/* Robot Room Cleaner | |
* | |
* [Hard] [AC:65.6% 27.9K of 42.6K] | |
* [filetype:javascript] | |
* | |
* Given a robot cleaner in a room modeled | |
* as a grid. | |
* | |
* Each cell in the grid can be empty or | |
* blocked. | |
* | |
* The robot cleaner with 4 given APIs can | |
* move forward, turn left or turn right. | |
* Each turn it made is 90 degrees. | |
* | |
* When it tries to move into a blocked | |
* cell, its bumper sensor detects the | |
* obstacle and it stays on the current | |
* cell. | |
* | |
* Design an algorithm to clean the entire | |
* room using only the 4 given APIs shown | |
* below. | |
* | |
* interface Robot { | |
* | |
* // returns true if next cell is open | |
* and robot moves into the cell. | |
* | |
* // returns false if next cell is | |
* obstacle and robot stays on the | |
* current cell. | |
* | |
* boolean move(); | |
* | |
* // Robot will stay on the same cell | |
* after calling turnLeft/turnRight. | |
* | |
* // Each turn will be 90 degrees. | |
* | |
* void turnLeft(); | |
* | |
* void turnRight(); | |
* | |
* // Clean the current cell. | |
* | |
* void clean(); | |
* | |
* } | |
* | |
* Example: | |
* | |
* Input: | |
* | |
* room = [ | |
* | |
* [1,1,1,1,1,0,1,1], | |
* | |
* [1,1,1,1,1,0,1,1], | |
* | |
* [1,0,1,1,1,1,1,1], | |
* | |
* [0,0,0,1,0,0,0,0], | |
* | |
* [1,1,1,1,1,1,1,1] | |
* | |
* ], | |
* | |
* row = 1, | |
* | |
* col = 3 | |
* | |
* Explanation: | |
* | |
* All grids in the room are marked by | |
* either 0 or 1. | |
* | |
* 0 means the cell is blocked, while 1 | |
* means the cell is accessible. | |
* | |
* The robot initially starts at the | |
* position of row=1, col=3. | |
* | |
* From the top left corner, its position | |
* is one row below and three columns | |
* right. | |
* | |
* Notes: | |
* | |
* The input is only given to initialize | |
* the room and the robot's position | |
* internally. You must solve this problem | |
* "blindfolded". In other words, you must | |
* control the robot using only the | |
* mentioned 4 APIs, without knowing the | |
* room layout and the initial robot's | |
* position. | |
* | |
* The robot's initial position will | |
* always be in an accessible cell. | |
* | |
* The initial direction of the robot will | |
* be facing up. | |
* | |
* All accessible cells are connected, | |
* which means the all cells marked as 1 | |
* will be accessible by the robot. | |
* | |
* Assume all four edges of the grid are | |
* all surrounded by wall. | |
* | |
* [End of Description] */ | |
/** | |
* // This is the robot's control interface. | |
* // You should not implement it, or speculate about its implementation | |
* function Robot() { | |
* | |
* // Returns true if the cell in front is open and robot moves into the cell. | |
* // Returns false if the cell in front is blocked and robot stays in the current cell. | |
* @return {boolean} | |
* this.move = function() { | |
* ... | |
* }; | |
* | |
* // Robot will stay in the same cell after calling turnLeft/turnRight. | |
* // Each turn will be 90 degrees. | |
* @return {void} | |
* this.turnLeft = function() { | |
* ... | |
* }; | |
* | |
* // Robot will stay in the same cell after calling turnLeft/turnRight. | |
* // Each turn will be 90 degrees. | |
* @return {void} | |
* this.turnRight = function() { | |
* ... | |
* }; | |
* | |
* // Clean the current cell. | |
* @return {void} | |
* this.clean = function() { | |
* ... | |
* }; | |
* }; | |
*/ | |
/** | |
* | |
* [1,1,1,1,1,0,1,1], | |
* [1,1,1,1,1,0,1,1], | |
* [1,0,1,1,1,1,1,1], | |
* [0,0,0,1,0,0,0,0], | |
* [1,1,1,1,1,1,1,1] | |
* | |
/** | |
* @param {Robot} robot | |
* @return {void} | |
*/ | |
var cleanRoom = function(robot) { | |
let dir = 0; | |
const cleaned = {}; | |
const flipDir = d => (d + 2) % 4; | |
const turnRight = () => { robot.turnRight(); dir = (dir + 1) % 4; }; | |
const setDir = (newDir) => { while (dir !== newDir) turnRight(); }; | |
const recurse = (x, y, moveDir) => { | |
robot.clean(); | |
if (cleaned[x + " : " + y] === true) return; | |
moveDir >= 0 && setDir(moveDir); | |
if (moveDir >= 0 && !robot.move()) { | |
return; | |
} else { | |
cleaned[x + " : " + y] = true; | |
// visit all non-clean adjacent squares | |
recurse(x, y - 1, 0); | |
recurse(x + 1, y, 1); | |
recurse(x, y + 1, 2); | |
recurse(x - 1, y, 3); | |
} | |
// move back to our last square | |
moveDir >= 0 && setDir(flipDir(moveDir)); | |
moveDir >= 0 && robot.move(); | |
}; | |
recurse(0, 0, -1); | |
}; |
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