Created
July 1, 2013 15:36
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Compute two strings levenshtein distance in mysql. from http://stackoverflow.com/questions/5322917/how-to-compute-similarity-between-two-strings-in-mysql
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DROP FUNCTION IF EXISTS levenshtein; | |
DELIMITER $$ | |
CREATE FUNCTION `levenshtein`( s1 text, s2 text) RETURNS int(11) | |
DETERMINISTIC | |
BEGIN | |
DECLARE s1_len, s2_len, i, j, c, c_temp, cost INT; | |
DECLARE s1_char CHAR; | |
DECLARE cv0, cv1 text; | |
SET s1_len = CHAR_LENGTH(s1), s2_len = CHAR_LENGTH(s2), cv1 = 0x00, j = 1, i = 1, c = 0; | |
IF s1 = s2 THEN | |
RETURN 0; | |
ELSEIF s1_len = 0 THEN | |
RETURN s2_len; | |
ELSEIF s2_len = 0 THEN | |
RETURN s1_len; | |
ELSE | |
WHILE j <= s2_len DO | |
SET cv1 = CONCAT(cv1, UNHEX(HEX(j))), j = j + 1; | |
END WHILE; | |
WHILE i <= s1_len DO | |
SET s1_char = SUBSTRING(s1, i, 1), c = i, cv0 = UNHEX(HEX(i)), j = 1; | |
WHILE j <= s2_len DO | |
SET c = c + 1; | |
IF s1_char = SUBSTRING(s2, j, 1) THEN | |
SET cost = 0; ELSE SET cost = 1; | |
END IF; | |
SET c_temp = CONV(HEX(SUBSTRING(cv1, j, 1)), 16, 10) + cost; | |
IF c > c_temp THEN SET c = c_temp; END IF; | |
SET c_temp = CONV(HEX(SUBSTRING(cv1, j+1, 1)), 16, 10) + 1; | |
IF c > c_temp THEN | |
SET c = c_temp; | |
END IF; | |
SET cv0 = CONCAT(cv0, UNHEX(HEX(c))), j = j + 1; | |
END WHILE; | |
SET cv1 = cv0, i = i + 1; | |
END WHILE; | |
END IF; | |
RETURN c; | |
END; | |
$$ | |
CREATE FUNCTION `levenshtein_ratio`( s1 text, s2 text ) RETURNS int(11) | |
DETERMINISTIC | |
BEGIN | |
DECLARE s1_len, s2_len, max_len INT; | |
SET s1_len = LENGTH(s1), s2_len = LENGTH(s2); | |
IF s1_len > s2_len THEN | |
SET max_len = s1_len; | |
ELSE | |
SET max_len = s2_len; | |
END IF; | |
RETURN ROUND((1 - LEVENSHTEIN(s1, s2) / max_len) * 100); | |
END; | |
$$ | |
DELIMITER ; |
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Hello friend, the above function, at all, is not reliable, the position and size of the string is not reliable comparison parameter. See a more precise function at https://gist.github.com/phpenterprise/be9560412824e5b05e1c1b3f38266b57, thanks!