Zip file on nodeJS using subprocess

zip.js

const path = require('path');
const { spawn } = require('child_process');

(async () => {
    try {
        await zip(path.resolve(__dirname, 'foo.js'), path.resolve(__dirname, 'bar.zip'));

        console.log('OK');
    } catch (err) {
        console.error('Failed to zip!', err);
    }

})();


function zip(inputFile, outputFile, timeout=(1000*60*5)) {
    return new Promise((resolve, reject) => {

        const subprocess = spawn('zip', [outputFile, inputFile], {
            shell: false,
            stdio: 'ignore',
            cwd: __dirname,
        });

        // subprocess.stdout.on('data', data=>console.log(data.toString()));
    
        //failed to spawn process
        subprocess.on('error', reject);
        
       const t = setTimeout(() => {
           subprocess.kill();
           reject(new Error('TIMEDOUT'));
        }, timeout);
    
        //process exited
        subprocess.on('exit', (code, signal) => {
            clearTimeout(t);
            if (code === 0) {
                resolve();
            }
            else { 
                reject(code || signal);
            }
        });
    });
}