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haskell fibonacci
fib = map fib' [0..] where
fib' 0 = 0; fib' 1 = 1; fib' n = (fib !! (n-1))+(fib !! (n-2))
@vigdorchik
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or linearly:

fib = map fst $ iterate ((n_2,n_1) -> (n_1, n_2+n_1)) (1,1)

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