Created
January 21, 2019 08:03
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To Generate the non-repeated characters of String. Given two integers X and Y, returns containing exactly X letters "A" and exactly Y letters "b". X defines maximum of character repetition.
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public class NonRepeatCharacters { | |
public static void main(String[] args) { | |
System.out.println("Answer is " + NonRepeatString(2, 5, 3)); | |
} | |
// n = Maximum number of repeation; | |
// x = 1st character with number of times. | |
// y -2nd character with number of times. | |
public static String NonRepeatString(int n, int X, int Y) { | |
String biggerString, smallerString; | |
int biggerCount, smallerCount; | |
if (n > X || n > Y) { | |
return "Invalid Solution"; | |
} | |
if (X >= Y) { | |
biggerString = "A"; | |
smallerString = "b"; | |
biggerCount = X; | |
smallerCount = Y; | |
} else { | |
biggerString = "b"; | |
smallerString = "A"; | |
biggerCount = Y; | |
smallerCount = X; | |
} | |
// A > NB + N | |
// if (biggerCount > 2 * smallerCount + 2) { | |
if (biggerCount > ((n * smallerCount) + n)) { | |
return "Invalid Value Entry"; | |
} | |
StringBuilder returnString = new StringBuilder(); | |
do { | |
if (biggerCount == smallerCount + (n - 1)) { | |
returnString.append(biggerString); | |
biggerCount--; | |
} else if (biggerCount == smallerCount) { | |
returnString.append(biggerString); | |
biggerCount--; | |
returnString.append(smallerString); | |
smallerCount--; | |
} else { | |
int nFinal = 0; | |
if (n < biggerCount) { | |
nFinal = n; | |
} else { | |
nFinal = biggerCount; | |
} | |
for (int i = 0; i < nFinal; i++) { | |
returnString.append(biggerString); | |
} | |
biggerCount -= n; | |
if (smallerCount > 0) { | |
int sFinal = 0; | |
if(n<=smallerCount){ | |
sFinal = n-1; | |
}else{ | |
sFinal = smallerCount; | |
} | |
for (int j = 0; j <sFinal; j++) { | |
returnString.append(smallerString); | |
} | |
smallerCount -= n-1; | |
} | |
} | |
} while (biggerCount > 0); | |
return returnString.toString(); | |
} | |
} |
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