afloesch

Jenkins in Docker (docker-in-docker)

Testing Jenkins flows on your local machine, or running Jenkins in production in a docker container can be a little tricky with a docker-in-docker scenario. You could install Jenkins to avoid any docker-in-docker issues, but then you have Jenkins on your machine, and the local environment is likely going to be a fairly different from the actual production build servers, which can lead to annoying and time-consuming issues to debug.

Build environment differences are precisely why there is a strong argument to be made to run build processes strictly in docker containers. If we follow the philosophy that every build step or action should run in a docker container, even the Jenkins server itself, then we get massive benefits from things like, total control over the build environment, easily modify the build environment without the possibility of adversely effecting other jobs, explicit and strongly controlled tool versions,

svoisen

onEnter : (String -> msg) -> Attribute msg
onEnter tagger =
    let
        isEnter code = 
            if code == 13 then
                Decode.succeed ""
            else
                Decode.fail ""
        decodeEnter =
            Decode.andThen isEnter keyCode

jecyhw

public class AjaxAwareAuthenticationEntryPoint extends LoginUrlAuthenticationEntryPoint {
    public AjaxAwareAuthenticationEntryPoint(String loginFormUrl) {
        super(loginFormUrl);
    }

    @Override
    public void commence(HttpServletRequest request, HttpServletResponse response, AuthenticationException authException) throws IOException, ServletException {
        String ajaxHeader = ((HttpServletRequest) request).getHeader("X-Requested-With");
        if ("XMLHttpRequest".equals(ajaxHeader)) {
            response.sendError(HttpServletResponse.SC_FORBIDDEN, "Ajax Request Denied (Session Expired)");

seemaullal

Before you started coding, you should have tried to think about this problem visually. It would probably help to actually make a stack and then an empty helper stack and think about how you can move elements around until one of the stacks contains all the elements in sorted order.

Here is an explanation of how the solution works– this is just an explanation of the algorithm and contains no code (at one point the video says that 8 is smaller than 2 instead of 8 is bigger than 2 but the solution is still correct):

(click on the image to be taken to the video)

The general idea is that you always pop the top element of the stack which you are sorting. You want to add this to the helper stack but first need to make sure that doing so won't make the helper stack unsorted.

When all elements from the original stack are in the helper stack (i.e. the original stack is empty), you n