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vire/q_example.js

Forked from jeffcogswell/q_example.js
Last active Aug 29, 2015
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What would you like to do?
// Q sample by Jeff Cogswell
/*===========
We want to call these three functions in sequence, one after the other:
First we want to call one, which initiates an ajax call. Once that
ajax call is complete, we want to call two. Once two's ajax call is
complete, we want to call three.
BUT, we don't want to just call our three functions in sequence, as this quick
demo will show. Look at this sample function and think about what order
the console.log calls will happen:
===========*/
function demo() {
$.ajax( {
url: '/',
success: function() {
console.log('AJAX FINISHED');
}
});
}
console.log('Calling demo');
demo();
console.log('Finished calling demo');
/*====
The function returns almost immediately, before the ajax call is complete.
That means we will likely see 'Finished calling demo' before we see the
results of the ajax call:
====*/
//Calling demo
//Finished calling demo
//AJAX FINISHED
/*====
If we want to chain a following function, when do we call it?
We call it from inside the success function:
====*/
function demo() {
$.ajax( {
url: '/',
success: function() {
console.log('AJAX FINISHED');
// >>>> THIS IS WHEN you would call another function <<<<<
}
});
}
/* ==============
Now let's try using q.
=============*/
function one() {
var deferred = Q.defer(); // Don't worry yet what this is
// until after you understand the flow
console.log("Starting one's ajax");
$.ajax( {
url: '/',
success: function() {
// Here's where you want to call the next function in the
// list if there is one. To do it, call deferred.resolve()
console.log('Finished with one. Ready to call next.');
deferred.resolve();
}
});
// The deferred object has a "promise" member,
// which has a "then" function
return deferred.promise;
}
function two() {
var deferred = Q.defer();
console.log("Starting two's ajax");
$.ajax( {
url: '/',
success: function() {
// Again, this is where you want to call the next function
// in the list if there is one.
console.log('Finished with two. Ready to call next.');
deferred.resolve();
}
});
// The deferred object has a "promise" member,
// which has a "then" function
return deferred.promise;
}
function three() {
var deferred = Q.defer();
console.log("Starting three's ajax");
$.ajax( {
url: '/',
success: function() {
// Again, this is where you want to call the next function
// in the list if there is one.
console.log('Finished with three. Ready to call next if there is one.');
deferred.resolve();
}
});
// The deferred object has a "promise" member, which has a "then" function
return deferred.promise;
}
// Test it out. Call the first. Pass the functions
// (without calling them, so no parentheses) into the then calls.
one()
.then(two)
.then(three);
/* =====
Think about where the "then" function comes from. Each function
creates a new defer instance and returns that object's promise
member. That promise object has a "then" function. On return
from the first function, you get back a defer function, and
call the "then" function, passing the *next* function that is
to be called. Internally, Q stores that function. When your
ajax call returns, in your "success" function, you call the
next function by calling deferred.resolve().
======*/
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