Detect no,of utf-8 chars in a line

detect_utf8.c

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

//utf-8 chars can be 4bytes long
#define U_MAX_BYTES 4

//counter to hold non ascii chars count
int count = 0;

int u_getc(FILE *stream, char *bytes) {
    /*
      utf chars start with 0,10,110,1110 which describes
      the length of utf8 char
      the following masks are to detect the length of utf8 char
    */
    int mask[] = {192, 224, 240}; 

    unsigned short i, j; 

    memset(bytes, 0, U_MAX_BYTES + 1);

    bytes[0] = getc(stream);
    if (bytes[0] == EOF) { 
        return 0; 
    } 
    
    //check the length of utf8 char
    i = 0;
    if ((bytes[0] & mask[0]) == mask[0]) i++;
    if ((bytes[0] & mask[1]) == mask[1]) i++;
    if ((bytes[0] & mask[2]) == mask[2]) i++;

    //if i is not 0 then its a non ascii char
    //ascii chars start with 0
    if(i > 0) count++;

    j = 0;
    while (j < i) {
        j++;
        bytes[j] = getc(stream);
    }

    return i + 1;
}

int main(int argc, char *argv[]) {
    char bytes[200]; 
    while (u_getc(stdin, bytes)) {
        //print non ascii count if we encounter a \n or EOF
        if((strcmp(bytes,"\n") == 0)){
          printf("%d\n", count);
          count = 0;
        }
    }
    
    if(count > 0) printf("%d", count);

    return 0; 
}

input_file

x√ab c
3 ∏x
abc cd
  I ♥ haskell, ♫ & ♘
    ɖ & Ɛ
€€€

output

1
1
0
3
2
3

gcc detect_utf8.c -Wall -lm
./a.out < input > output