Overloading methods with generic arguments

GenericOverloading.java

// Since generics in Java are removed at compile-time, we cannot overload methods
// based on generic types

// Below class does not compile:
// Erasure of method Foo(T1) is the same as another method in type Test<T1,T2>
// Erasure of method Foo(T2) is the same as another method in type Test<T1,T2>
class Generic<T1, T2> {
    void Foo(T1 arg) {
    }
	
    void Foo(T2 arg) {
    }
}

// Using dummy type guards, we can enable overloading

// Dummy types, just need to be different
class TypeGuard1 { }
class TypeGuard2 { }

// Compiles, guard argument doesn't have to be provided (unless T1 and T2 are 
// the same)
class GenericWithGuards<T1, T2> {
    void Foo(T1 arg, TypeGuard1...guard) {
    }
	
    void Foo(T2 arg, TypeGuard2...guard) {
    }

    static void Demo() {
        GenericWithGuards<String, Integer> g = new GenericWithGuards<>();
		
        // The right function gets called depending on argument type    
        g.Foo("Hello");
        g.Foo(42);
    }
}