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@voldmar /
Last active Feb 14, 2017

What would you like to do?
Show all signals receivers in Django project (quickfixed to work with Django 1.10)
# coding:utf-8
from sys import modules
import gc
import inspect
import six
from import BaseCommand
from django.dispatch.dispatcher import Signal, WeakMethod
'vim': '{path}:{line}:{name}',
'human': '{name} in line {line} of {path}',
class Command(BaseCommand):
help = 'Show all signals receivers'
def add_arguments(self, parser):
parser.add_argument('--line_format', choices=FORMATS.keys(), default='human',
help='Line format (available choices: {0})'.format(', '.join(FORMATS))
def handle(self, *args, **options):
line_format = options['line_format']
if line_format not in FORMATS:
raise CommandError('format must be on of {0}, not {1}'.format(line_format, FORMATS.keys()))
msg = FORMATS[line_format]
signals = [obj for obj in gc.get_objects() if isinstance(obj, Signal)]
for signal in signals:
for receiver in signal.receivers:
_, receiver = receiver
func = receiver()
name = func.__qualname__ if six.PY3 else func.__name__
print(msg.format(name=name, line=inspect.getsourcelines(func)[1], path=inspect.getsourcefile(func)))

@voldmar - this is really helpful - thanks for posting. Is it possible to get the name of the Signal as well as the receiver function - I've tried myself but can't work out how to do it.

Can you please indicate, preferably in-line, what Django version this relates to (or was tested on). It does not work on 1.7 for me (ImportError: cannot import name saferef)

I made a fork here that lists only model signals by model and signal type. Tested with django 1.7.


voldmar commented Feb 14, 2017

@runekaagaard Oh, thank you! I haven’t used Django for a while and haven’t seen comments. Thanks a lot for you fork

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