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<?php | |
//-------------------------------------------------------- | |
// Example: | |
// | |
// $cars = [ | |
// ['id' => 999, 'value' =>'CARS', 'parent_id' => 0 ], | |
// ['id' => 11, 'value' =>'Toyota', 'parent_id' => 999], | |
// ['id' => 1, 'value' =>'Avalon', 'parent_id' => 11 ], | |
// ['id' => 2, 'value' =>'Corolla', 'parent_id' => 11 ], | |
// ['id' => 3, 'value' =>'Camry', 'parent_id' => 11 ], |
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<?php | |
/** | |
* Looks for unquoted keys in a json string and fixes them ie: {a:"b"} => {"a":"b"} | |
* @param string $string A json string that is suspect | |
* @return string A valid json string | |
*/ | |
function fix_json($string){ | |
// (no qupte) (word) (no quote) (semicolon) | |
$regex = '/(?<!")([a-zA-Z0-9_]+)(?!")(?=:)/i'; |
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function getBase64FromImageUrl(url) { | |
var img = new Image(); | |
img.setAttribute('crossOrigin', 'anonymous'); | |
img.onload = function () { | |
var canvas = document.createElement("canvas"); | |
canvas.width =this.width; | |
canvas.height =this.height; |
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$(document).ready(function() { | |
// Function to convert an img URL to data URL | |
function getBase64FromImageUrl(url) { | |
var img = new Image(); | |
img.crossOrigin = "anonymous"; | |
img.onload = function () { | |
var canvas = document.createElement("canvas"); | |
canvas.width =this.width; | |
canvas.height =this.height; | |
var ctx = canvas.getContext("2d"); |
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sudo add-apt-repository ppa:sergey-dryabzhinsky/php53 | |
sudo apt-get update | |
sudo apt-get install php53-common php53-cli | |
# to see a list of available packages: | |
# apt-cache search php53 | |
# ex.: sudo apt-get install php53-mod-mysql | |
# Apache module: | |
sudo apt-get install libapache2-mod-php53 |
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// Save a password hash: | |
// ====================== | |
$options = [ | |
'cost' => 11, | |
]; | |
// Get the password from post | |
$passwordFromPost = $_POST['password']; | |
$hash = password_hash($passwordFromPost, PASSWORD_BCRYPT, $options); |
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--- | |
METHOD 1 | |
This should roughly sort the items on distance in MySQL, and should work in SQLite. | |
If you need to sort them preciser, you could try using the Pythagorean theorem (a^2 + b^2 = c^2) to get the exact distance. | |
--- | |
SELECT * | |
FROM table | |
ORDER BY ((lat-$user_lat)*(lat-$user_lat)) + ((lng - $user_lng)*(lng - $user_lng)) ASC |
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mysql-events | |
https://www.npmjs.com/package/sql-events-listener | |
A node.js package that watches a MySQL database and runs callbacks on matched events. | |
Install | |
npm install @rodrigogs/mysql-events | |
MySQL configuration: | |
Enabling Binary Logging. Use SHOW BINARY LOGS query to determine whether Binlog has been enabled or not. |
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//------------------------------------------------------- | |
// Sort an Array of Objects in JavaScript | |
// | |
// To sort an array of objects, you use the sort() method | |
// and provide a comparison function that determines | |
// the order of objects. | |
//------------------------------------------------------- | |
//------------------------------------------------------- | |
// Suppose that you have an array of employee objects as follows: |
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Number.prototype.formatMoney = function(c, d, t){ | |
c = isNaN(c = Math.abs(c)) ? 2 : c; | |
d = d == undefined ? "." : d; | |
t = t == undefined ? "," : t; | |
var n = this; | |
var s = n < 0 ? "-" : ""; | |
var i = String(parseInt(n = Math.abs(Number(n) || 0).toFixed(c))); | |
var j = (j = i.length) > 3 ? j % 3 : 0; | |
return s + (j ? i.substr(0, j) + t : "") + i.substr(j).replace(/(\d{3})(?=\d)/g, "$1" + t) + (c ? d + Math.abs(n - i).toFixed(c).slice(2) : ""); |
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