C++11 result_of_t

gistfile1.txt

#include <type_traits>
#include <iostream>
 
struct S {
    int operator()(int) { return 1; }
};

int normal(int) { return 1;}


int main()
{
    // Using double () here changes type from function to pointer to function.
    // Apparently result_of_t does not like function type,  per http://stackoverflow.com/a/30919688/126517
    using N = decltype((normal));
    
    std::result_of_t<S(int)> v1 = 10;
    std::result_of_t<N(int)> v2 = 10;
    return v1 + v2;
}