small script to prune extreneous sooc jpg's - we want raw_dir == jpg_dir

raw_diff.sh

#!/usr/bin/sh

# small script to prune extreneous sooc jpg's - we want raw_dir == jpg_dir
# takes one arg: full path to raw_dir
# requires 'trash-cli' package: https://github.com/andreafrancia/trash-cli

RAW_DIR="${1}" # user passes raw directory path
JPG_DIR=$(find "$RAW_DIR" -mindepth 1 -maxdepth 1 -name "*sooc" -type d) # only look dirs ending in "sooc"

# get all files matching .{ext}, return only the basename
# modified from: https://stackoverflow.com/questions/26935515/in-linux-how-to-compare-two-directories-by-filename-only-and-get-list-of-result
getfiles() {
	find "$1" -maxdepth 1 -type f -regextype posix-extended -regex ".*\.(RAF|JPG)" \
	-exec bash -c 'for f in "$@"; do basename "${f%.*}"; done' "" {} + | sort;
}

# diff raw_dir -> jpg_dir. Compare basename only (minus ext)
# returns files that exist in jpg_dir and not raw_dir
diff=( $(grep -vxFf <(getfiles "$RAW_DIR") <(getfiles "$JPG_DIR")) )

# stdout results of diff. Add results to "dirty" array
dirty=()
for filename in ${diff[@]}; do
  filepath="${JPG_DIR}/${filename}.JPG"
  dirty+=( "${filepath}" )
  echo "$filepath"
done

# ask before trashing extreneous sooc jpg's
printf ">  \e[31mTrash\e[39m the above \033[1m%s\033[0m jpg's from \e[33m%s\e[39m (Y/n) " ${#diff[@]} "$(basename "${JPG_DIR}")"
read answer
if [ "$answer" != "${answer#[Yy]}" ] ;then
  for filename in ${diff[@]}; do
	printf '>> \e[31mTrashing\e[39m \e[33m%s\e[39m\n' "${filename}"
  done
  trash "${dirty[@]}" # for extra safety, use trash-cli rather than rm
  printf '>> \e[31mTrashed\e[39m \033[1m%s\033[0m files\n' ${#diff[@]}
fi