find palindrome date

find_palindrome_date.py

#!/usr/bin/python
# -*- coding: utf-8 -*-

# find palindrome dates from today
# One date is same whatever you read it from left or right,
# like "20111102", "20200202"... we'll call it palindrome date.

import datetime

today = datetime.datetime.today()
oneday = datetime.timedelta(days=1)

while True:
    left = "%s" % today.year
    right = "%02d%02d" % (today.month, today.day)
    if left == right[::-1]:
        print "%s:%s" % (left, right)
    today = today + oneday

# next a few dates:
#20200202
#20211202
#20300302
#20400402
#20500502
#20600602
#20700702
#20800802
#20900902
#21100112
#...