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@vznvzn
Created August 20, 2016 00:37
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def f1(n)
n = (n * 3 + 1) / 2 while (n % 2 == 1)
n /= 2 while (n % 2 == 0)
return n
end
def seq2(n)
l = [n]
n1 = n
begin
l << (n = f1(n))
end while (n >= n1 && n != 1)
return l
end
def d(s)
c = s.split('').select { |x| x == '1' }.size
d = s.empty? ? 0 : c.to_f / s.length
return (0.5 - d).abs, d
end
def r(x)
return sprintf("%.3f", x).to_f
end
def mnmx(l)
return l.min, l.max
end
def stat(l)
return if (l.empty?)
t = t2 = 0
l.each \
{
|x|
t += x
t2 += x ** 2
}
c = l.size
a = t.to_f / c
z = t2.to_f / c - a ** 2
sd = Math.sqrt(z < 0 ? 0 : z)
return l.size, a, sd, l.max, l.min
end
def mx(n)
l = seq2(n)
d1, d = d(n.to_s(2))
ls = l.size
return {'ls' => ls, 'd' => d}
end
def three(x)
n = x['n']
p = x['p']
p2 = p + 1
n2 = n | (1 << p2)
x2 = x.merge('p' => p2)
x3 = {'n' => n2, 'p' => p2}.merge(mx(n2))
return [x2, x3]
end
def hard(c)
l1 = []
x = {'n' => 1, 'p' => 0}.merge(mx(1))
b = {}
a = []
c.times \
{
|n|
$stderr.puts(n) if (n % 100 == 0)
l1 << x
ls = x['ls']
a[ls] = 0 if (a[ls].nil?)
a[ls] += 1
three(x).each \
{
|x2|
ls = x2['ls']
b[ls] = b.fetch(ls, []) + [x2]
}
j = (2..a.size).find { |i| a[i].nil? || a[i] < 50 }
j = a.size if (j.nil?)
k = b.keys.sort.find { |i| i >= j }
k = b.keys.min if (k.nil?)
i = (0...b[k].size).to_a.sort_by { |x| -b[k][x]['d'] }[rand([b[k].size, 3].min)]
x = b[k].delete_at(i)
}
return l1
end
l = hard(20000)
b = {}
l.each_with_index \
{
|x, i|
ls = x['ls']
b[ls] = b.fetch(ls, []) + [x.merge({'i' => i})]
}
b.sort.each \
{
|k, l|
l1 = l.map { |x| x['d'] }
puts([k, stat(l1)].join("\t"))
}
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