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@vznvzn
Created August 27, 2016 01:02
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def f1(n)
n = (n * 3 + 1) / 2 while (n % 2 == 1)
n /= 2 while (n % 2 == 0)
return n
end
def seq2(n)
l = [n]
n1 = n
l << (n = f1(n)) while (n >= n1 && n != 1)
return l
end
def d(s)
c = s.split('').select { |x| x == '1' }.size
d = c.to_f / s.length
return d
end
def val(n)
return {'ls' => seq2(n).size, 'd' => d(n.to_s(2))}
end
def stat(l)
return 0, 0, 0, 0 if (l.empty?)
t = t2 = 0
l.each \
{
|x|
t += x
t2 += x ** 2
}
c = l.size
a = t.to_f / c
z = t2.to_f / c - a ** 2
sd = Math.sqrt(z < 0 ? 0 : z)
return l.size, a, sd, l.max, l.min
end
def fmt(l)
return l.map { |x| sprintf("%.3g", x).to_f }
end
l = [{'n' => 1, 'p' =>0}.merge(val(1))]
t1 = Time.now.to_i
seen = {}
80.times \
{
l1 = []
l2 = []
while (!l.empty?)
x = l.shift
p = x['p'] + 1
n = x['n']
x1 = x.dup
x1['p'] = p
l2.push(x1)
x2 = {}
n |= (1 << p)
x2['n'] = n
x2['p'] = p
x2.merge!(val(n))
if (x2['ls'] > x['ls']) then
l2.push(x2)
l1.push(x2) if (!seen.member?(x2['n']))
seen[x2['n']] = nil
end
end
lx = l1.map { |x| x['d'] }
ly = l1.map { |x| x['ls'] }
puts([l2.size, fmt(stat(lx)), fmt(stat(ly))].join("\t"))
$stdout.flush
l = l2
}
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