Created
June 15, 2013 16:43
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GCJ2013 Round3 A 満点が取れる解法を実装したコード
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#include <cstdio> | |
#include <cstring> | |
#include <cmath> | |
#include <vector> | |
#include <list> | |
#include <string> | |
#include <set> | |
#include <map> | |
#include <queue> | |
#include <stack> | |
#include <algorithm> | |
#include <iostream> | |
#include <sstream> | |
using namespace std; | |
typedef long long int64; | |
const int inf = (int)1e9; | |
const int size = 37; | |
int64 calcCost(int right, int64 low, vector<int64> &x) | |
{ | |
int64 ret = 0; | |
for(int i = 0; i <= right; ++i) | |
ret += low - x[i]; | |
for(int i = right + 1; i < size; ++i) | |
ret += max((low + 1) - x[i], 0LL); | |
return ret; | |
} | |
double calcExpected(int right, int64 low, vector<int64> &x) | |
{ | |
double ret = 0; | |
for(int i = 0; i <= right; ++i) | |
ret += (low - x[i]) * (double)(size - 1); | |
ret = ret / (right + 1); | |
return ret; | |
} | |
int64 calcMax(int right, int64 budget, vector<int64> &x) | |
{ | |
int64 lb = x[right], ub = (int64)1e16; | |
while(ub - lb > 1) { | |
int64 mid = (ub + lb) / 2; | |
if(calcCost(right, mid, x) <= budget) | |
lb = mid; | |
else | |
ub = mid; | |
} | |
return lb; | |
} | |
double calc(int right, int64 budget, vector<int64> &x) | |
{ | |
int64 low = x[right]; | |
double ans = 0; | |
vector<int64> val; | |
for(int i = right; i < size; ++i) | |
val.push_back(x[i]); | |
for(int i = right + 1; i < size; ++i) | |
val.push_back(x[i] - 1); | |
val.push_back(calcMax(right, budget, x)); | |
for(int i = 0; i < val.size(); ++i) { | |
double expected = calcExpected(right, val[i], x); | |
int64 cost = calcCost(right, val[i], x); | |
if(cost <= budget) | |
ans = max(ans, expected - cost); | |
} | |
return ans; | |
} | |
int main() | |
{ | |
int casenum; | |
scanf("%d", &casenum); | |
for(int testcase = 1; testcase <= casenum; ++testcase) { | |
int64 budget; | |
int n; | |
vector<int64> x; | |
scanf("%lld%d", &budget, &n); | |
x.resize(size); | |
for(int i = 0; i < n; ++i) | |
scanf("%lld", &x[i]); | |
for(int i = n; i < size; ++i) | |
x[i] = 0LL; | |
sort(x.begin(), x.end()); | |
double ans = 0; | |
for(int i = 0; i < size; ++i) | |
ans = max(ans, calc(i, budget, x)); | |
printf("Case #%d: %.8lf\n", testcase, ans); | |
} | |
return 0; | |
} | |
/* ハラスメントに負けず */ | |
/* 0完太陽にも負けず */ | |
/* はやく人権を獲得したい */ |
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