Function to determine if a string contains a space in bash

has-space.sh

#!/bin/bash -eux

function has-space {
  [[ "$1" != "${1%[[:space:]]*}" ]] && return 0 || return 1
}

if has-space "sadfsdf" ; then
  echo "SPACE"
fi

if ! has-space "fassfsdgsdg" ; then
  echo "NOSPACE"
fi