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@wfwef
Created October 2, 2013 06:39
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help!!
# Q3.
"1 2 3 4 5 6 [7] 6 5 4 3 2 1 [0] 1 2 [3] 2 1 0 [-1] 0 1 2 3 4 [5] [4] 5 6"
def pingpong(n):
"""Return the nth element of the ping-pong sequence.
>>> pingpong(7)
7
>>> pingpong(8)
6
>>> pingpong(15)
1
>>> pingpong(21)
-1
>>> pingpong(22)
0
>>> pingpong(30)
6
>>> pingpong(68)
2
>>> pingpong(69)
1
>>> pingpong(70)
0
>>> pingpong(71)
1
>>> pingpong(72)
0
>>> pingpong(100)
2
"""
"*** YOUR CODE HERE ***"
def pingpongdir(n, direction):
if n == 1:
return 1
elif direction:
if has_seven(n) or n % 7 == 0:
return pingpongdir(n-1, False) + 1
else:
return pingpongdir(n-1, True) + 1
else:
if has_seven(n) or n % 7 == 0:
return pingpongdir(n-1, True) - 1
else:
return pingpongdir(n-1, False) - 1
return pingpongdir(n, False)
@arctan5x
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great code baby

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