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@wh5a
Created January 1, 2013 03:05
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CUDA Array Sum with Reduction
// MP 4 Reduction
// Given a list (lst) of length n
// Output its sum = lst[0] + lst[1] + ... + lst[n-1];
// Due Tuesday, January 15, 2013 at 11:59 p.m. PST
#include <wb.h>
#define BLOCK_SIZE 512 //@@ You can change this
#define wbCheck(stmt) do { \
cudaError_t err = stmt; \
if (err != cudaSuccess) { \
wbLog(ERROR, "Failed to run stmt ", #stmt); \
return -1; \
} \
} while(0)
__global__ void total(float * input, float * output, int len) {
//@@ Load a segment of the input vector into shared memory
__shared__ float partialSum[2 * BLOCK_SIZE];
unsigned int t = threadIdx.x, start = 2 * blockIdx.x * BLOCK_SIZE;
if (start + t < len)
partialSum[t] = input[start + t];
else
partialSum[t] = 0;
if (start + BLOCK_SIZE + t < len)
partialSum[BLOCK_SIZE + t] = input[start + BLOCK_SIZE + t];
else
partialSum[BLOCK_SIZE + t] = 0;
//@@ Traverse the reduction tree
for (unsigned int stride = BLOCK_SIZE; stride >= 1; stride >>= 1) {
__syncthreads();
if (t < stride)
partialSum[t] += partialSum[t+stride];
}
//@@ Write the computed sum of the block to the output vector at the
//@@ correct index
if (t == 0)
output[blockIdx.x] = partialSum[0];
}
int main(int argc, char ** argv) {
int ii;
wbArg_t args;
float * hostInput; // The input 1D list
float * hostOutput; // The output list
float * deviceInput;
float * deviceOutput;
int numInputElements; // number of elements in the input list
int numOutputElements; // number of elements in the output list
args = wbArg_read(argc, argv);
wbTime_start(Generic, "Importing data and creating memory on host");
hostInput = (float *) wbImport(wbArg_getInputFile(args, 0), &numInputElements);
numOutputElements = numInputElements / (BLOCK_SIZE<<1);
if (numInputElements % (BLOCK_SIZE<<1)) {
numOutputElements++;
}
hostOutput = (float*) malloc(numOutputElements * sizeof(float));
wbTime_stop(Generic, "Importing data and creating memory on host");
wbLog(TRACE, "The number of input elements in the input is ", numInputElements);
wbLog(TRACE, "The number of output elements in the input is ", numOutputElements);
wbTime_start(GPU, "Allocating GPU memory.");
//@@ Allocate GPU memory here
cudaMalloc(&deviceInput, sizeof(float) * numInputElements);
cudaMalloc(&deviceOutput, sizeof(float) * numOutputElements);
wbTime_stop(GPU, "Allocating GPU memory.");
wbTime_start(GPU, "Copying input memory to the GPU.");
//@@ Copy memory to the GPU here
cudaMemcpy(deviceInput, hostInput, sizeof(float) * numInputElements, cudaMemcpyHostToDevice);
wbTime_stop(GPU, "Copying input memory to the GPU.");
//@@ Initialize the grid and block dimensions here
dim3 dimGrid(numOutputElements, 1, 1);
dim3 dimBlock(BLOCK_SIZE, 1, 1);
wbTime_start(Compute, "Performing CUDA computation");
//@@ Launch the GPU Kernel here
total<<<dimGrid, dimBlock>>>(deviceInput, deviceOutput, numInputElements);
cudaDeviceSynchronize();
wbTime_stop(Compute, "Performing CUDA computation");
wbTime_start(Copy, "Copying output memory to the CPU");
//@@ Copy the GPU memory back to the CPU here
cudaMemcpy(hostOutput, deviceOutput, sizeof(float) * numOutputElements, cudaMemcpyDeviceToHost);
wbTime_stop(Copy, "Copying output memory to the CPU");
/********************************************************************
* Reduce output vector on the host
* NOTE: One could also perform the reduction of the output vector
* recursively and support any size input. For simplicity, we do not
* require that for this lab.
********************************************************************/
for (ii = 1; ii < numOutputElements; ii++) {
hostOutput[0] += hostOutput[ii];
}
wbTime_start(GPU, "Freeing GPU Memory");
//@@ Free the GPU memory here
cudaFree(deviceInput);
cudaFree(deviceOutput);
wbTime_stop(GPU, "Freeing GPU Memory");
wbSolution(args, hostOutput, 1);
free(hostInput);
free(hostOutput);
return 0;
}
@nanofaroque
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Does it work? I follow your steps but getting error.

@altimadc
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Works but is 10000 times slower than cpu. I seldom get a GPU implementation that beats CPU especially when I make the CPU parallel. I don't get it!

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