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Basic implementation of COUNTLESS8
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from itertools import combinations | |
from functools import reduce | |
def countless8(a,b,c,d,e,f,g,h): | |
"""Extend countless5 to countless8. Same deal, except we also | |
need to check for matches of length 4.""" | |
sections = [ a, b, c, d, e, f, g, h ] | |
# PICKN = PICK with N arguments | |
p2 = lambda q,r: q * (q == r) # PICK2 | |
p3 = lambda q,r,s: q * ( (q == r) & (r == s) ) # PICK3 | |
p4 = lambda p,q,r,s: p * ( (p == q) & (q == r) & (r == s) ) # PICK4 | |
lor = lambda x,y: x + (x == 0) * y # short circuiting logical or | |
# important to use generator expressions here to reduce peak memory usage | |
results4 = ( p4(x,y,z,w) for x,y,z,w in combinations(sections, 4) ) | |
results4 = reduce(lor, results4) | |
results3 = ( p3(x,y,z) for x,y,z in combinations(sections, 3) ) | |
results3 = reduce(lor, results3) | |
# We can always use our shortcut of omitting the last element | |
# for N choose 2 | |
results2 = ( p2(x,y) for x,y in combinations(sections[:-1], 2) ) | |
results2 = reduce(lor, results2) | |
return reduce(lor, [ results4, results3, results2, h ]) |
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