Created
August 21, 2012 12:02
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http://qiita.com/items/cbc3af152ee3f50a822f の問題をhaskellで解いてみた
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import Data.List | |
import Test.HUnit | |
poker :: String -> String | |
poker = check . split | |
split :: String -> [(String, String)] | |
split ('D':'1':'0':xs) = [("D", "10")] ++ split xs | |
split ('C':'1':'0':xs) = [("C", "10")] ++ split xs | |
split ('S':'1':'0':xs) = [("S", "10")] ++ split xs | |
split ('H':'1':'0':xs) = [("H", "10")] ++ split xs | |
split ('D':numberString:xs) = ("D", [numberString]) : split xs | |
split ('C':numberString:xs) = ("C", [numberString]) : split xs | |
split ('S':numberString:xs) = ("S", [numberString]) : split xs | |
split ('H':numberString:xs) = ("H", [numberString]) : split xs | |
split [] = [] | |
countSameRank :: [String] -> String -> Int | |
countSameRank [] x = 0 | |
countSameRank (y:ys) x | |
| x == y = 1 + (countSameRank ys x) | |
| otherwise = countSameRank ys x | |
check :: [(String, String)] -> String | |
check cards | |
| maxCount == 4 = "4K" | |
| maxCount == 3 = if rankCounts !! 1 == 2 | |
then "FH" | |
else "3K" | |
| maxCount == 2 = if rankCounts !! 1 == 2 | |
then "2P" | |
else "1P" | |
| otherwise = "--" | |
where | |
ranks = map snd cards | |
seeds = nub ranks | |
rankCounts = reverse . sort $ map (countSameRank ranks) seeds | |
maxCount = maximum rankCounts | |
tests = test ["FH" ~=? poker "D3C3C10D10S3"] |
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