create set of visibility for each character

set_visibility.py

characters = [
    {'id': 1, 'visible': set()},
    {'id': 2, 'visible': set()},
    {'id': 3, 'visible': set()},
    {'id': 4, 'visible': set()},
    {'id': 5, 'visible': set()},
    {'id': 6, 'visible': set()},
]

mapchunks = [
    set((1,2,3)), 
    set((3,4,6)),
    set((5,2,1,3))
]

for ch in characters:
    for chunk in mapchunks:
        if ch['id'] in chunk:
            ch['visible'] |= chunk

    print(f"player: {ch['id']} has {len(ch['visible'])} visible players: {ch['visible']}")
    
# output:
# player: 1 has 4 visible players: {1, 2, 3, 5}
# player: 2 has 4 visible players: {1, 2, 3, 5}
# player: 3 has 6 visible players: {1, 2, 3, 4, 5, 6}
# player: 4 has 3 visible players: {3, 4, 6}
# player: 5 has 4 visible players: {1, 2, 3, 5}
# player: 6 has 3 visible players: {3, 4, 6}


# Copilot recommended a slight improvement:
# # Create a dictionary mapping each character id to its visible set
# visible_dict = {ch['id']: ch['visible'] for ch in characters}

# # Iterate over the mapchunks once
# for chunk in mapchunks:
#     for id in chunk:
#         if id in visible_dict:
#             visible_dict[id] |= chunk

# # Print the results
# for ch in characters:
#     print(f"player: {ch['id']} has {len(ch['visible'])} visible players: {ch['visible']}")