wootfish

from functools import wraps


def _read_memo(fname="memo"):
    with open(fname, "r") as f:
        memo = eval(f.read())
    return memo


def _write_memo(memo, fname="memo"):

wootfish

# this script samples the distributions of the k closest peers to randomly
# selected addresses and saves these to data files


import datetime
from multiprocessing import Process, Event
import os
import pprint
import random

wootfish

# imports and basic notebook setup
from cStringIO import StringIO
import numpy as np
import scipy.ndimage as nd
import PIL.Image
from IPython.display import clear_output, Image, display
from google.protobuf import text_format

from random import randint

wootfish

# imports and basic notebook setup
from cStringIO import StringIO
import numpy as np
import scipy.ndimage as nd
import PIL.Image
from IPython.display import clear_output, Image, display
from google.protobuf import text_format

import os
import sys

wootfish

#!/usr/bin/python2.7

# imports and basic notebook setup
from cStringIO import StringIO
import numpy as np
import scipy.ndimage as nd
import PIL.Image
from IPython.display import clear_output, Image, display
from google.protobuf import text_format

wootfish

#!/usr/bin/python2.7

# imports and basic notebook setup
from cStringIO import StringIO
import numpy as np
import scipy.ndimage as nd
import PIL.Image
from IPython.display import clear_output, Image, display
from google.protobuf import text_format

wootfish

Python 2.7.8 (default, Oct 18 2014, 12:50:18) 
[GCC 4.9.1] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import sympy
>>> x1, x2, x3 = sympy.symbols('x1 x2 x3')
>>> y1, y2, y3 = sympy.symbols('y1 y2 y3')
>>> 
>>> def distance(p1, p2):
...     # still using the Pythagorean Theorem
...     x = (p1[0] - p2[0]) ** 2

wootfish

Python 2.7.8 (default, Oct 18 2014, 12:50:18) 
[GCC 4.9.1] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> def distance(p1, p2):
...     # this just uses the Pythagorean Theorem
...     x = (p1[0] - p2[0]) ** 2
...     y = (p1[1] - p2[1]) ** 2
...     return (x + y) ** 0.5
... 
>>> def herons(a, b, c):