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Count log events per hour using awk, for a log file containing messages prefixed with date and time e.g., '2016-04-18 02:03:07'
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| $awk -F: '/logMessageOfInterest/ {counts[$1] = counts[$1] + 1; } END { for (val in counts) print val, counts[val]; }' LOG.TXT | sort |
If you want to turn that into a script see http://unix.stackexchange.com/questions/120788/pass-shell-variable-as-a-pattern-to-awk
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Example output, showing lack of events in the 7 o'clock hour
2016-04-19 05 832
2016-04-19 06 496
2016-04-19 08 467
2016-04-19 09 471