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The Fibonacci sequence in JavaScript: how my implementation is 161% faster.
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// This code is the companion for my article: | |
// "Program performance: cleaner !== better" | |
// You can read it here: | |
// https://www.infinium.earth/article/program-performance | |
// How many interations each function is | |
// called to check the average. | |
const ITERATIONS = 100; | |
const BASE_N = 200; | |
const average = a => a.reduce((t, c) => t + c) / a.length; | |
// My implementation: | |
const myFib = (n) => { | |
let res = []; | |
// Using a while-loop here was ever so | |
// slightly slower. | |
// Moreover, using a ternary operator was | |
// slightly slower. | |
for (let i = 0; i < n; ++i) { | |
let v; | |
if (i > 1) { | |
v = res[i - 1] + res[i - 2]; | |
} else { | |
v = i; | |
} | |
res.push(v); | |
} | |
return res; | |
} | |
// Their solution: | |
const theirFib = n => { | |
return Array.from({ length: n }).reduce( | |
(acc, val, i) => acc.concat(i > 1 ? acc[i - 1] + acc[i - 2] : i), | |
[] | |
); | |
} | |
const checkAverage = (f) => { | |
let s1 = []; | |
for (let i = 0; i < ITERATIONS; ++i) { | |
const t0 = performance.now(); | |
f(BASE_N); | |
const t1 = performance.now(); | |
s1.push(t1 - t0); | |
} | |
return `${average(s1)} - ${f.name}` | |
}; | |
console.log(checkAverage(myFib)); | |
console.log(checkAverage(theirFib)); |
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