[groovy] list dirs/files (dir first and sort as name)

file_list.groovy

import groovy.io.*

def listfiles(dir) {
	dlist = []
	flist = []
	new File(dir).eachDir {dlist << it.name }
	dlist.sort()
	new File(dir).eachFile(FileType.FILES, {flist << it.name })
	flist.sort()
	return (dlist << flist).flatten()
}

fs = listfiles(".")
fs.each {
	println it
}

Nice Script, thanks @yangkun

I am trying to use the same script to list all the files present in a folder while running Jenkins pipeline, but its throwing error, can you help me with that!

So if I understand you correctly you want to use the script in the Jenkins pipeline. I haven't tried that yet, but I know that a loop and then more calls from sh-instructions in the scripted-pipeline have to be converted to functions and have to be marked as such.
I am using the script in connection with "Active Choises Reactive Parameter". Works very well under Windows. On Mac OSX, I'm having permissions issues since the upgrade to Catalina.

What do you get for an error in the console log?

Well, I figured it out, and I was running it on a Linux machine.
Thanks, @herculosh for a Quick reply :)

Below is my code, Hopefully, it will useful for someone, I am running this code as a groovy script in Jenkins Pipeline

**@NonCPS
def fetFilenamesFromDir(def dir, def list){
dir.eachFileRecurse (FileType.FILES) { file ->
file = file.toString()
if (file.endsWith("json")){
list << file
}
}
}

node('master'){
def list = []

def dir = new File("dirPathToBeDefined")
fetFilenamesFromDir(dir,list)

for (i in list){
print i
print("\n")
}**