yanring

import time
import torch
from torch import nn
from torch.nn import Conv2d, Module, Linear, BatchNorm2d, ReLU
import torch.nn.functional as F
from torch.nn.modules.utils import _pair
from torch.autograd import Function

class DropBlock2D(nn.Module):
    r"""Randomly zeroes 2D spatial blocks of the input tensor.

yanring

蚂蚁

• 官网 金融业务安全解决方案
• 官网 业务反欺诈
• 蚂蚁金服TRaaS技术风险防控平台解密
• 蚂蚁金服助力银行搭建高性能智能风控体系
• 风控策略产品经理：案例蚂蚁金服-支付宝的风控策略（浅析）

文章的结构如下，可以挑选感兴趣看看：
（1）一个案例
（2）案例的支付宝风控策略

yanring

# for manjaro 需要手动切换内核
sudo pacman -S openssh nfs-utils
sudo systemctl enable sshd
sudo systemctl start sshd



# for ubuntu
sudo apt-get install --reinstall linux-headers-$(uname -r) linux-headers-generic build-essential dkms

yanring

#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
int n,res=9999999;
double max_d=0;
double d[52];
int p[52];
void dfs(int index, double sum_d, int sum_gold){
	if(sum_d>=max_d){

yanring

#include <iostream>
#include <vector>
#include <algorithm>
#include <math.h>
using namespace std;

int main()
{
	// input
	int n,w,tmp,res=0,flag;

yanring

#include <iostream>
#include <string>
using namespace std;
int daxie[26],xiaoxie[26];
string str;
void scan(string str){
	int len = str.size();
	for(char c : str){
		if(c <= 'Z' and c>='A'){
			daxie[c-'A']++;

yanring

update 完整版迁移至：https://github.com/yanring/jianzhi-Offer-Leetcode

7. 重建二叉树 -> https://leetcode.com/problems/construct-binary-tree-from-preorder-and-inorder-traversal/
12. √矩阵中的路径 -> https://leetcode.com/problems/word-search/
13. 机器人的运动范围 -> 没找到
14. 剪绳子（dp） -> 没找到
15. √二进制中1的个数 -> https://leetcode.com/problems/number-of-1-bits/ ->（升级版）https://leetcode.com/problems/counting-bits/

yanring

begintime='2014-01-01';
endtime='2017-01-01';
total_value = 1000000;
name=['YNBY','GLDQ','WLY','SQJT','WHHX','GTDL','ZSYH','ZGPA','GTJA','DEEJ']';
YNBY=w.wsd('000538.SZ','LOW,OPEN,CLOSE,HIGH',begintime,endtime); %调入云南白药股票四数据
GLDQ=w.wsd('000651.SZ','LOW,OPEN,CLOSE,HIGH',begintime,endtime); %调入格力电器数据
num=size(YNBY,1); %得到总历史数据个数
data =[];%所有股票的数据
a=[0.1,0.1,0.1,0.1,0.1,0.1,0.1,0.1,0.1,0.1,0.1]; %总仓位配比，为云南白药30%，格力电器30%，现金40%
p=[1,1,1];  %三者初始成本价格均为1，即云南白药单位一份1，格力电器单位一份1，现金单位一份为1