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/* | |
Given a string, find the longest palindromic substring. | |
Maintains right upper half of the table. | |
*/ | |
public class LongestPalindromicSubstring { | |
// complexity: time O(n^2), space O(n^2) | |
static int findLPS(String S) { | |
int n = S.length(); | |
boolean[][] memo = new boolean[n][n]; | |
// length 1 substring is a palindrome | |
// diagonal | |
int max = 1; | |
for (int i=0; i<n; i++) { | |
memo[i][i] = true; | |
} | |
// check length 2 substring | |
int start = 0; | |
for (int i=0; i<n-1; i++) { | |
if (S.charAt(i) == S.charAt(i+1)) { | |
memo[i][i+1] = true; | |
start = i; | |
max = 2; | |
} | |
} | |
// check length longer than 2 | |
for (int k = 3; k<=n; k++) { | |
for (int i=0; i<n-k+1; i++) { | |
// ending index | |
int j = i + k -1; | |
if (memo[i+1][j-1] && (S.charAt(i) == S.charAt(j))) { | |
memo[i][j] = true; | |
if (k > max) { | |
start = i; | |
max = k; | |
} | |
} | |
} | |
} | |
System.out.println("longest: " + S.substring(start, start+max)); | |
return max; | |
} | |
public static void main(String[] args) { | |
String S = "forgeeksskeegfor"; | |
System.out.println(findLPS(S)); | |
} | |
} | |
/* | |
References: | |
http://www.geeksforgeeks.org/longest-palindrome-substring-set-1/ | |
http://www.programcreek.com/2013/12/leetcode-solution-of-longest-palindromic-substring-java/ | |
*/ |
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