Test whether the exception is Ctrl + C in Pycharm's Python console

is_keyboard_interrupt.py

"""
You can use PyCharm's Python console and use Ctrl + C, 
if you catch the exception that PyCharm raises when Ctrl + C is pressed. 
I wrote a short function below called `is_keyboard_interrupt` 
that tells you whether the exception is KeyboardInterrupt, 
including PyCharm's. 
If it is not, simply re-raise it. 
I paste a simplified version of the code below.

When it is run:

- type 'help' and press Enter to repeat the loop.
- type anything else and press Enter to check that ValueError is handled properly.
- Press Ctrl + C to check that KeyboardInterrupt is caught, including in PyCharm's python console.

Note: This doesn't work with PyCharm's debugger console 
(the one invoked by "Debug" rather than "Run"), 
but there the need for Ctrl + C is less, 
because you can simply press the pause button.

See this answer & the original question 
on Stack Overflow: https://stackoverflow.com/a/60900672/2565317 
"""


def is_keyboard_interrupt(exception):
    # The second condition is necessary for it to work with the stop button
    # in PyCharm Python console.
    return (type(exception) is KeyboardInterrupt
            or type(exception).__name__ == 'KeyboardInterruptException')


if __name__ == '__main__':
    try:
        def print_help():
            print("To exit type exit or Ctrl + c can be used at any time")
        print_help()

        while True:
            task = input("What do you want to do? Type \"help\" for help:- ")
            if task == 'help':
                print_help()
            else:
                print("Invalid input.")

                # to check that ValueError is handled separately
                raise ValueError()

    except Exception as ex:
        try:
            # Catch all exceptions and test if it is KeyboardInterrupt, native or
            # PyCharm's.
            print('Exception type: %s' % type(ex).__name__)
            if not is_keyboard_interrupt(ex):
                print('Not KeyboardInterrupt!')
                raise ex

            print('KeyboardInterrupt caught as expected.')
            exit()

        except ValueError:
            print('ValueError!')