Finds the distinct factors of n

distinct_factors.py

def factor(n):
    
    factors = []

    for x in range(1,n):

        if len(factors) > 1 and x == factors[-1][1] or len(factors) > 1 and factors[-1][0] == factors[-1][1]:
            break
        elif n % x == 0:
            if x != (n / x):
                factors.append([x,(n / x)])
                
    return factors

def re_factor(number_to_factor):
    
    factors = factor(number_to_factor)
    factored_factors = []
    quads = []
    new = set()
    done = []

    for factor_set in factors:
        temp_list = []
        
        if factor(factor_set[0]):
            temp_list.append(factor(factor_set[0]))
        if factor(factor_set[1]):
            temp_list.append(factor(factor_set[1]))
        
        factored_factors.append(temp_list)

    for result in factored_factors:
        if len(result) > 1:
            for pair in result[0]:
                for secondary_pair in result[1]:
                    quads.append([pair[0], pair[1], secondary_pair[0], secondary_pair[1]])

    for quad in quads:
        if len(set(quad)) >= 4:
            new.add(frozenset(quad))
    
    for item in new:
        done.append(sorted(list(item)))

    return done

print re_factor(144)